Q 1 ) If the cost price of 6 articles is equal to the selling price of 4 articles find - Maths - Comparing Quantities

Question

Q 1 ) If the cost price of 6 articles is equal to the selling price
of 4 articles find the profit percent

Q 2 ) A man buys 10 chocolates for rupees 3 and sells them as 8
chocolates for rupees 3 find the profit percent

Q 3) A man sold two paintings at rupees 924 each On one he gains 20
% and the other he loses 20 % How much does he gain or lose in the
whole transaction ?

Q 4 ) Find the Selling price when :

1
(i) Cost price is = rupees 12 50 and Loss = 13 %
3

Manbar Singh · Accepted Answer

1
Let the CP of 6 articles = Rs xCP of 1 article = Rsx6Now, SP of 4 articles = Rs xSP of 1 article = Rsx4Since SP > CP
 so there ocurrs a loss
Now profit = SP - CP = x4-x6 = 3x-2x12 = Rsx12Now, profit % = profitCP×100% = x/12x/6×100% = 50%2
CP of 10 chocolates = Rs 3CP of 1 chocolate = Rs310Now, SP of 8 chocolates = Rs 3SP of 1 chocolate = Rs38Since SP > CP, so there ocurrs a profit
Now, profit = SP - CP = 38-310 = 15-1240 = Rs340Now, profit % = profitCP×100% = 3/403/10×100% = 25%3
SP of first painting = Rs 924Profit % = 20%⇒profitCP×100% = 20%⇒profitCP×100 = 20⇒5 profit = CP⇒5SP-CP = CP⇒5SP - 5CP = CP⇒6CP = 5SP⇒CP = 56×924 = Rs 770SP of second painting = Rs 924    loss % = 20%⇒lossCP×100% = 20%⇒lossCP×100 = 20⇒5loss = CP⇒5CP-SP = CP⇒5CP - 5SP = CP⇒4CP = 5SP⇒CP = 54×924 = Rs 1155Total CP of both paintings = 770 + 1155 = Rs 1925Total SP of both paintings = 924 + 924 = Rs 1848Since Total CP > total SP, so there ocurrs a lossLoss = Total CP - Total SP = 1925 - 1848 = Rs 77Now, Loss % = lossCP×100% = 771925×100% = 4%

Kindly ask the remaining query in the different thread