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Q-1. On factorising (a3 + 3√3b3) we get :-

$a^{3} + 3 \sqrt{3} b^{3} = a^{3} + {(\sqrt{3} b)}^{3} = (a + \sqrt{3} b) (a^{2} + \sqrt{3} a b + {(\sqrt{3} b)}^{2}) = (a + \sqrt{3} b) (a^{2} + \sqrt{3} a b + 3 b^{2})$

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