011-40705070  or
Select Board & Class
• Select Board
• Select Class
Subject: Math , asked on 15/1/13

Rs 6500 were divided equally among a certain no: of persons. Had there been 15 more persons each would have got rs 30 less. Find the original no: of persons

Let the original number of persons be  n.

âˆ´ Amount received by each person =

If there were 15 more person,

then

Number of persons =  n  + 15

New amount received by each person

âˆ´According to the question,

Amount received by each person â€“ New amount received by each person = Rs 30

Thus, the original number of persons is 50.

This conversation is already closed by Expert

• 2
View More

let number of people be X.

1st equation = 6500/X

2nd equation= 6500/ 15+X

asper question when 15 people werwe more then 30 rupees were less with everyone.

therefore, 6500/X- 6500/ X+15 = 30

6500(1/X-1/X+15) = 30

6500(X+15- X / X2 + 15X) = 30

6500(15/X2+ 15X)= 30

6500(15) = 30(X2 + 15X)

6500(15) = 30X2 +30(15X)  [TAKING 15 COMMON]

6500  = 2X2  + 30X

0  =  2X2 +30X - 6500 [TAKING 2 COMMON]

0  =  X2 +15X - 3250

0  = X2 +(65X - 50X) - 3250[MIDDLE TERM FACTORISATION]

0  =  X2 +65X - 50X - 3250

0  =  X(X +65) - 50(X+ 65)

THEREFORE , X = 50 PEOPLE.

• 1

## Popular Chapters

Start a Conversation
You don't have any friends yet, please add some friends to start chatting
Unable to connect to the internet. Reconnect
friends:
{{ item_friends["first_name"]}} {{ item_friends["last_name"]}} {{ item_friends["subText"] }}