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Rs 6500 were divided equally among a certain no: of persons. Had there been 15 more persons each would have got rs 30 less. Find the original no: of persons

thank you ...waiting for your answer..

Asked by Mughilan S.(student) , on 15/1/13

Answers

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let number of people be X.

1st equation = 6500/X

2nd equation= 6500/ 15+X

asper question when 15 people werwe more then 30 rupees were less with everyone.

therefore, 6500/X- 6500/ X+15 = 30

6500(1/X-1/X+15) = 30

6500(X+15- X / X2 + 15X) = 30

6500(15/X2+ 15X)= 30

6500(15) = 30(X2 + 15X)

6500(15) = 30X2 +30(15X) [TAKING 15 COMMON]

6500 = 2X2 + 30X

0 = 2X2 +30X - 6500 [TAKING 2 COMMON]

0 = X2 +15X - 3250

0 = X2 +(65X - 50X) - 3250[MIDDLE TERM FACTORISATION]

0 = X2 +65X - 50X - 3250

0 = X(X +65) - 50(X+ 65)

THEREFORE , X = 50 PEOPLE.

Posted by Tadepalli Manoj...(student)on 15/1/13

EXPERT ANSWER

Let the original number of persons be n.

∴ Amount received by each person =

If there were 15 more person,

then

Number of persons = n + 15

New amount received by each person

∴According to the question,

Amount received by each person – New amount received by each person = Rs 30

Thus, the original number of persons is 50.

Posted by Gursheen kaur(MeritNation Expert)on 21/1/13

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