011-40705070  or  
Call me
Download our Mobile App
Select Board & Class
  • Select Board
  • Select Class
 

Rs 6500 were divided equally among a certain no: of persons. Had there been 15 more persons each would have got rs 30 less. Find the original no: of persons

thank you ...waiting for your answer..

Asked by Mughilan S.(student) , on 15/1/13


Become Expert
Score more in Math
Start Now with Video Lessons, Sample Papers, Revision Notes & more for Class-X - CBSE 

EXPERT ANSWER

Let the original number of persons be  n.

 

∴ Amount received by each person = 

 

If there were 15 more person, 

then

Number of persons =  n  + 15

 

New amount received by each person 

 

∴According to the question,

Amount received by each person – New amount received by each person = Rs 30

 

Thus, the original number of persons is 50.

Posted by Gursheen kaur(MeritNation Expert)on 21/1/13

This conversation is already closed by Expert

More Answers

let number of people be X. 

1st equation = 6500/X

2nd equation= 6500/ 15+X

asper question when 15 people werwe more then 30 rupees were less with everyone. 

therefore, 6500/X- 6500/ X+15 = 30

  6500(1/X-1/X+15) = 30

  6500(X+15- X / X2 + 15X) = 30

  6500(15/X2+ 15X)= 30

  6500(15) = 30(X2 + 15X)

  6500(15) = 30X2 +30(15X)  [TAKING 15 COMMON]

  6500  = 2X2  + 30X

  0  =  2X2 +30X - 6500 [TAKING 2 COMMON]

  0  =  X2 +15X - 3250

  0  = X2 +(65X - 50X) - 3250[MIDDLE TERM FACTORISATION]

  0  =  X2 +65X - 50X - 3250

  0  =  X(X +65) - 50(X+ 65)

  THEREFORE , X = 50 PEOPLE.

Posted by Tadepalli Manoj...(student)on 15/1/13

Ask a QuestionHave a doubt? Ask our expert and get quick answers.
Show me more questions

close