SHOW THAT THE MEDIAN OF A TRIANGLE DIVIDES IT INTO TWO TRIANGLES OF EQUAL AREA

Let the triangle be triangle ABC........
And D be the midpoint of side BC.......
And side AE be the perpendicular from point A to side BC such that
B=E=C.
now,
A(triangle ADB)/A(triangle ADC) = (1/2 * AD * DB) / (1/2 * AD * DC)
AS area of a triangle is equal to half the product of its base and height
hence A(triangle ADB)/A(triangle ADC) = DB/BC
= (1/2 * BC) / (1/2 * BC)
AS point D is midpoint of side BC
hence A(triangle ADB)/A(triangle ADC) = 1
hence A(triangle ADB) = A(triangle ADC)
hence we can say that a median of a triangle divides it into two triangles of equal area..........

hope this answer satisfies ur query :-))))

Let the triangle be triangle ABC.....
And D be the midpoint of side BC........
And side AE be the perpendicular from point A to side BC such that
B=E=C.
now,
A(triangle ADB)/A(triangle ADC) = (1/2 * AD * DB) / (1/2 * AD * DC)
AS area of a triangle is equal to half the product of its base and height
hence A(triangle ADB)/A(triangle ADC) = DB/BC
= (1/2 * BC) / (1/2 * BC)
AS point D is midpoint of side BC
hence A(triangle ADB)/A(triangle ADC) = 1
hence A(triangle ADB) = A(triangle ADC)
hence we can say that a median of a triangle divides it into two triangles of equal area............

Let the triangle be triangle ABC.........
and D be the midpoint of side BC........

and side AE be the perpendicular from point A to side BC such that
B=E=C
now,
A(triangle ADB)/A(triangle ADC) = (1/2 * AD * DB) / (1/2 * AD * DC)
AS area of a triangle is equal to half the product of its base and height
hence A(triangle ADB)/A(triangle ADC) = DB/BC
= (1/2 * BC) / (1/2 * BC)
AS point D is midpoint of side BC
hence A(triangle ADB)/A(triangle ADC) = 1
hence A(triangle ADB) = A(triangle ADC)
hence we can say that a median of a triangle divides it into two triangles of equal area........