sin^2A and cos^2A are roots of ax2+bx+c Prove that a+b = 4c - Maths - Polynomials

Question

sin^2A and cos^2A are roots of ax2+bx+c
Prove that a+b = 4c

Anuradha Sharma · Accepted Answer

ax2+bx+c=0 has roots sin2A, cos2ASo sum of roots = sin2A+ cos2A =-baor b = -aor a+b = 0
1Now product of roots,  sin2A× cos2A=caBut we cannot see any further result so kindly recheck the question

sin^2A and cos^2A are roots of ax2+bx+c. Prove that a+b = 4c

sin^2A and cos^2A are roots of ax2+bx+c.

Prove that a+b = 4c