sin inverse sin 3pi/5????

sin^-1(sin 3pi/5)

=sin^-1(sin (Pi-3pi/5)) because:sin x= sin (pi-x)

=sin^-1(sin 2pi/5)

=2pi//5. because:sin^-1(sin x)=x

Note(imp) -it is not 3 pi/5 since it doesnt come in the interval[-pi/2,pi/2]

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