Let I = ∫sin xsin x + a dx=∫sin x + a - asin x + a dx=∫sin x+a - asin x + a dx=∫sinx + a cos a - cosx+a sin asin x + a dx=∫cos a - cotx+a sin a dx=x cos a - sin a log sinx+a + C

∫sinx/sin(x+a)dx

Let I = \int \frac{\sin x}{\sin (x + a)} d x = \int \frac{\sin (x + a - a)}{\sin (x + a)} d x = \int \frac{\sin [(x + a) - a]}{\sin (x + a)} d x = \int \frac{\sin (x + a) . \cos a - \cos (x + a) . \sin a}{\sin (x + a)} d x = \int [\cos a - c o t (x + a) \sin a] d x = x \cos a - \sin a . \log |\sin (x + a)| + C

View Full Answer