solve
21 x^2=2(2x+1)

Dear Student,

21 x^{2} = 2 (2 x + 1) \Rightarrow 21 x^{2} = 4 x + 2 \Rightarrow 21 x^{2} - 4 x - 2 = 0 \Rightarrow x = \frac{4 \pm \sqrt{{(- 4)}^{2} - 4 \times 21 \times (- 2)}}{2 \times 21} [Using, x = \frac{- b \pm \sqrt{b^{2} - 4 ac}}{2 a}] \Rightarrow x = \frac{4 \pm \sqrt{16 + 168}}{42} \Rightarrow x = \frac{4 \pm 2 \sqrt{46}}{42} \Rightarrow x = \frac{2 \pm \sqrt{46}}{21}

Hope this information will clear your doubts about this topic.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Regards

View Full Answer

solve 21 x^2=2(2x+1)

solve
21 x^2=2(2x+1)