solve for x-1/x-2 + x-3/x-4 =10/3

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Varun.Rawat answered this

Refer the following link :
https://www.meritnation.com/ask-answer/question/factorize-x-1-x-8-125x-1-x-2-x-3-x-4-10-3/equations-and-inequations/2888115

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mayanklahoti98... answered this

i want answer of this

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music_maniac answered this

x-1/x-2 + x-3/x-4 = 10 /3 .....dis is de given equation..

u mus take de LCM

i.e. (x-1)(x-4) / (x-2) (x-4) = 10/3

i.e. x²-4 - x + 4 +x² -2x - 3x +6 / x² -4x - 2x +8 =10/3

i.e. 2x² - 10x +10 / x² - 6x +8 = 10/3

wen u cross multiply..u get..

3 ( 2x² - 10x + 10) = 10(x² - 6x + 8)

we get de final equation as ... -4x² + 30x - 50 = 0

takin de common factor... we get de equation as... -2x² + 15x - 25 = 0

we must multiply -1 on both de sides of de equation...

so de equation wil b..... 2x² - 15x +25 = 0

usin de factorisation method we get.... (x² -10x) (-5x+25) = 0

i.e . 2x(x-5) -5(x-5) = 0

i.e. (x-5)(2x-5) = 0...

which implies dat the roots of dis equation are...2x-5=0 i.e. 5/2

and x-5 = 0 ..i.e.5

hence de roots are 5/2 and 5

i hope this helps u ..if it did thumbs up plz!!!!!!!!!!

Shwetha J.m answered this

Hi Bipul, Here is the answer to your question. It is given that

Thus, the values of x satisfying the given equation is 5 or 5/2 Hope! You got the answer. Cheers!

Priyansh answered this

srres

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Gaurav Shrivastava answered this

i am agree to both jahanavi and shewtha

Sushant answered this

Given question
x-1/x-2 + x-3/x-4 = 10/3

First take the LCM of x-2 & x-4.
Solve ahead

(x-1)(x-4) + (x-3)(x-2) = 10/3
_______________________

(x-2)(x-4)

Now By multiplying following you get ..

x²-4x-x+4 + x²-2x-3x+6 = 10/3
__________________________

x²-4x-2x+8

After solving

2x²-10x+10 = 10/3
_____________

x²-6x+8

Then Cross Multiply The Equation

3(2x²-10x+10x)=10(x²-6x+8)

After solving it you get......

4x²-30x+50=0

Factorise it .....

After factorising you will get

(4x-10)(x-5) = 0

From here you will get the value of x.

x=5/2 or x=5

Thanks You