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Solve - sin2x - sin4x + sin6x=0

$Given: \sin 2 x - \sin 4 x + \sin 6 x = 0 \Rightarrow (\sin 6 x + \sin 2 x) - \sin 4 x = 0 \Rightarrow 2 \sin 4 x \cos 2 x - \sin 4 x = 0 \Rightarrow \sin 4 x (2 \cos 2 x - 1) = 0 \Rightarrow \sin 4 x = 0 \cos 2 x = \frac{1}{2} \Rightarrow 4 x = n π, n \in z or 2 x = 2 n π \pm \frac{π}{3} n \in z \Rightarrow x = \frac{n π}{4}, n \in z or x = n π \pm \frac{π}{6} n \in z$

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