Solve using cross multiplication method:ax + by = c,bx + ay = 1+ c Share with your friends Share 14 Manbar Singh answered this The given equations are :ax + by - c = 0bx + ay - 1 + c = 0Comparing the above 2 equations with standard equation, a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0, we geta1 =a ; b1 = b ; c1 = -ca2 = b ; b2 = a ; c2 = -1 + cNow, by cross multiplication, we know that, xb1c2-b2c1 = ya2c1-a1c2 = 1a1b2-a2b1⇒x-b1+c+ac = y-bc+a1+c = 1a2 - b2⇒x-b - bc + ac = y-bc + a + ac =1a2 - b2⇒ x-b - bc + ac = 1a2 - b2 and y-bc + a + ac =1a2 - b2⇒x = -b - bc + aca2 - b2 and y = -bc + a + aca2 - b2 38 View Full Answer
