It is also known as Thales Theorem. It states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points , then the other two sides are divided in the same ratio. Posted by Hayat Gandhi(student)

It is also known as Thales Theorem. It states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points , then the other two sides are divided in the same ratio. Posted by Hayat Gandhi(student)

It is also known as Thales Theorem. It states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points , then the other two sides are divided in the same ratio. Posted by Hayat Gandhi(student)

It is also known as Thales Theorem. It states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points , then the other two sides are divided in the same ratio Posted by Hayat Gandhi(student)

It is also known as Thales Theorem. It states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points , then the other two sides are divided in the same ratio Posted by Hayat Gandhi(student)

It is also known as Thales Theorem. It states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points , then the other two sides are divided in the same ratio Posted by Hayat Gandhi(student)

the father of bpt izz thales so it izz know as thales theorem also :if a line izz drawn parallel 2 one side of a triangle 2 interscet the other 2 sides in distinct point then the other 2 sides r divided in the same ratio.if u wanna no converse of bpt reply me. Posted by Sonia Verma(student)

the father of bpt izz thales so it izz know as thales theorem also :if a line izz drawn parallel 2 one side of a triangle 2 interscet the other 2 sides in distinct point then the other 2 sides r divided in the same ratio.if u wanna no converse of bpt reply me. Posted by Sonia Verma(student)

the father of bpt izz thales so it izz know as thales theorem also :if a line izz drawn parallel 2 one side of a triangle 2 interscet the other 2 sides in distinct point then the other 2 sides r divided in the same ratio.if u wanna no converse of bpt reply me. Posted by Sonia Verma(student)

STATEMENT = If a line is drawn parallel to one side of a triangle divides the other two sides proportionly. OR BPT http://i25.tinypic.com/2r2olz6.jpg GIVEN = IN TRIANGLE ABC DE||BC TO PROVE = AD = AE BD CE CONSTRUCTION = DRAW DM AND EN PERPENDICULAR TO AC AND AD RESPECTIVELY. JOIN BE AND CE PROOF = ar.(TRIANGLE ADE) = 1 x AE x DM 2 ar.(TRIANGLE DEC) = 1 x CE X DM 2 ar.(TRIANGLE ADE) = 1 x AE x DM ar.(TRIANGLE DEC) 2 1 x CE x DM 2 ar.(TRIANGLE ADE) = AE -------------( i ) ar.(TRIANGLE DEC) CE ar.(TRIANGLE ADE) = 1 x AD x EN ar.(TRIANGLE BDE) 2 1 x BD x EN 2 ar.(TRIANGLE ADE) = AD ar.(TRINAGLE BDE) BD TRIANGLE BDE AND DEC ARE HAVING SAME BASE AND ARE LYING BETWEEN SAME PARALLEL 'S SO, ar.(TRIANGLE BDE) = ar.(TRIANGLE DEC) ar.(TRIANGLE ADE) = AD -----------( ii ) ar.(TRIANGLE DEC) BD FROM ( i ) AND ( ii ) AD = AE BD CE HENCE, PROVED Posted by Kaushiki(student)

STATEMENT = If a line is drawn parallel to one side of a triangle divides the other two sides proportionly. OR BPT http://i25.tinypic.com/2r2olz6.jpg GIVEN = IN TRIANGLE ABC DE||BC TO PROVE = AD = AE BD CE CONSTRUCTION = DRAW DM AND EN PERPENDICULAR TO AC AND AD RESPECTIVELY. JOIN BE AND CE PROOF = ar.(TRIANGLE ADE) = 1 x AE x DM 2 ar.(TRIANGLE DEC) = 1 x CE X DM 2 ar.(TRIANGLE ADE) = 1 x AE x DM ar.(TRIANGLE DEC) 2 1 x CE x DM 2 ar.(TRIANGLE ADE) = AE -------------( i ) ar.(TRIANGLE DEC) CE ar.(TRIANGLE ADE) = 1 x AD x EN ar.(TRIANGLE BDE) 2 1 x BD x EN 2 ar.(TRIANGLE ADE) = AD ar.(TRINAGLE BDE) BD TRIANGLE BDE AND DEC ARE HAVING SAME BASE AND ARE LYING BETWEEN SAME PARALLEL 'S SO, ar.(TRIANGLE BDE) = ar.(TRIANGLE DEC) ar.(TRIANGLE ADE) = AD -----------( ii ) ar.(TRIANGLE DEC) BD FROM ( i ) AND ( ii ) AD = AE BD CE HENCE, PROVED Posted by Kaushiki(student)

STATEMENT = If a line is drawn parallel to one side of a triangle divides the other two sides proportionly. OR BPT http://i25.tinypic.com/2r2olz6.jpg GIVEN = IN TRIANGLE ABC DE||BC TO PROVE = AD = AE BD CE CONSTRUCTION = DRAW DM AND EN PERPENDICULAR TO AC AND AD RESPECTIVELY. JOIN BE AND CE PROOF = ar.(TRIANGLE ADE) = 1 x AE x DM 2 ar.(TRIANGLE DEC) = 1 x CE X DM 2 ar.(TRIANGLE ADE) = 1 x AE x DM ar.(TRIANGLE DEC) 2 1 x CE x DM 2 ar.(TRIANGLE ADE) = AE -------------( i ) ar.(TRIANGLE DEC) CE ar.(TRIANGLE ADE) = 1 x AD x EN ar.(TRIANGLE BDE) 2 1 x BD x EN 2 ar.(TRIANGLE ADE) = AD ar.(TRINAGLE BDE) BD TRIANGLE BDE AND DEC ARE HAVING SAME BASE AND ARE LYING BETWEEN SAME PARALLEL 'S SO, ar.(TRIANGLE BDE) = ar.(TRIANGLE DEC) ar.(TRIANGLE ADE) = AD -----------( ii ) ar.(TRIANGLE DEC) BD FROM ( i ) AND ( ii ) AD = AE BD CE HENCE, PROVED Posted by Kaushiki(student)