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State the Principle of reversibility of light

Asked by Sugeerthaa Redd...(student), on 14/9/09

The principle that if a beam of light is reflected back on itself, it will traverse the same path or paths as it did before reversal.

The principle of reversibility states that light will follow exactly the same path if its direction of travel is reversed.

Hence:

Using Snell 's Law,

 sin i sin r = 1 n 2 sin r sin i = 2 n 1
 1 n 2= 1 2 n 1

It follows that

 1 n 2= 1 2 n 1

Posted by Daffodils(student), on 14/9/09

Sorry ,

Using Snell 's Law,

 sin i sin r = 1 n 2 sin r sin i = 2 n 1
 1 n 2= 1 2 n 1

It follows that

Posted by Daffodils(student), on 14/9/09

 1 n 2= 1 2 n 1

this is the final equation.Sorry again

Posted by Daffodils(student), on 14/9/09

how

Posted by dipenaariwala.....(student), on 23/3/11

when light strikes any reflecting surface, then it goes in the same medium . if mirror is placed at right angle to the reflected ray then it returns in the same path from where it incident without any deviation

Posted by masoom786raza9....(student), on 24/3/11

show that incident ray of light is parallel to the emergent ray of light when light falls obliquely on a side of a rectangular glass slab

Posted by Aravind Nair(parent), on 25/3/11

i don 't know

we can prove this by a expiriment using a glass salb

Posted by abhinandan_gupt...(student), on 27/3/11

since the opposite faces or refracting surfaces are parallel incident ray and emergent ray are ll

Posted by manishr213...(student), on 21/2/13

The answer is : We know that "ANGLE i = ANGLE e" & "ANGLE R1 = ANGLE R2". As External & internal Angles r equal. The lines are Parallel

Posted by Aravind Skipper(student), on 13/3/13

when light strikes any reflecting surface, then it goes in the same medium . if mirror is placed at right angle to the reflected ray then it returns in the same path from where it incident without any deviation

Posted by Sambit Kumar Si...(student), on 13/3/13