The angle of elevation of the top Q of a vertical tower PQ from point X on the ground is 60 degree.At a point Y 40m vertically above X the angle of elevation is 45 degree .Find the height Of the tower PQ and distance XQ.
In YRQ, we have
⇒ YR = x
or XP = x [ As YR = XP ] ...... (1)
Now, In ∆ XPQ, we have
On rationalising the denominator, we get
So, height of the tower, PQ = x + 40 = 54.64 + 40 = 94.64 metres
Now in ∆ XPQ, we have
