THE BOND DISSOCIATION ENERGIES OF GASEOUS H2 ,Cl2 ,HCl ARE 104,58,103 Kcal RESPECTIVELY THE ENTHALPY OF FORMATION OF HCl - Chemistry - Chemical Kinetics

Question

THE BOND DISSOCIATION ENERGIES OF GASEOUS H2 ,Cl2 ,HCl ARE
104,58,103 Kcal RESPECTIVELY THE ENTHALPY OF FORMATION OF HCl GAS
WOULD BE ?IN THE SOLUTION FOR THIS QUESTION ,THE AVERAGE OF ALL THE
BOND DISSOCIATION ENERGY IS FOUND W HY IS IT SO?

Raveena Sharma · Accepted Answer

1 The chemical equation for the formation of HCl is :

H2 + Cl2 →2 HCl
2 Bond dissociation energy = Bonds broken - Bonds formed
= (104 + 58) - 2 (103) = - 44 Kcal
3 Thus we see that we do not take average of all,but applied the
formula above

THE BOND DISSOCIATION ENERGIES OF GASEOUS H2 ,Cl2 ,HCl ARE 104,58,103 Kcal RESPECTIVELY .THE ENTHALPY OF FORMATION OF HCl GAS WOULD BE ?IN THE SOLUTION FOR THIS QUESTION ,THE AVERAGE OF ALL THE BOND DISSOCIATION ENERGY IS FOUND.W HY IS IT SO?