The centres of 2 circles with radii 8 cm and 3 cm are 13 cm apart .A direct common tangent touches the circle at A and B respectively .What is the length of AB ?


We have,OA is radius and AB is tangent, therefore OAB=90°PB is radius and AB is tangent, therefore PBA=90°PB=8 cmOA=3 cmOP=13 cmDraw OMPB.MP=8-3=5 cmNow, OMP is right angled triangle.OM2+MP2=OP2OM2=OP2-MP2OM2=132-52OM2=169-25OM2=144OM=12 cmNow, ABMO is a rectangle.AB=OM=12 cmHence, AB=12 cm

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