The diagonals of a rhombus are 24cm and 10cm .Find the perimeter of the rhombus Share with your friends Share 0 Varun.Rawat answered this Let ABCD be the rhombus in which AC and BD are the diagonals.Now, AC = 24 cm; BD = 10 cmWe know that, diagonals of a rhombus bisect each other at right angle.Now, OA = OC = 12 cm and OB = OD = 5 cmAlso, ∠AOB = ∠BOC = ∠COD = ∠DOA = 90°In ∆AOB, AB2 = OA2+OB2 Pythagoras theorem⇒AB2 = 122 + 52⇒AB2 = 144+25⇒AB2 = 169⇒AB = 13 cmNow, perimeter of ABCD = 4AB = 4×13 = 52 cm 1 View Full Answer Rituraj Sharma answered this to find perimter of rhombus perimter of rhombus=sum of all side =24cm +24cm+10cm+10cm =68cm 1