The element chromium exists in bcc lattice with unit cell is edge 2 88 * 10^-10 m The density - Chemistry - The Solid State

Question

The element chromium exists in bcc lattice with unit cell is edge 2
88 * 10^-10 m The density is 7 2 * 10³ kg/m³ How many
atoms does 52 * 10^-3 kg of chromium contain ?

Geetha · Accepted Answer

Volume of the unit cell =a3 = 2
88 ×10-103 =  23
9 × 10-30 m3 = 23
9 × 10-24 cm3 Volume of chromium atom = massdensity = 52 ×10-3 kg7
20 × 103 kg/m3 =52 ×10-3 kg7
20 × 103 × 10-6 kg/cm3  = 7
22 cm3Number of unit cell = 7 2223
9 × 10-24 = 0
3021 × 1024 = 3
021 × 1023 unit cellSince the unit cell is bcc, each cell has 2 atoms per unit cellSo the total number of atoms = 2 ×3
021 × 1023  = 6
042 × 1023 atoms

The element chromium exists in bcc lattice with unit cell is edge 2.88 * 10^-10 m. The density is 7.2 * 10³ kg/m³. How many atoms does 52 * 10^-3 kg of chromium contain ?