The LCM of 2 numbers is 12 times their HCF .The sum of their LCM and HCF is 403.If one of them is 93,then other number is

a)134 b) 124 c)128 d) 310

Let LCM =12x

HCF = x

sum of LCM and HCF = 403

=>12x +x = 403

=> 13x = 403

=> x =31

As we know, Product of two numbers = product of their LCM and HCF

first number is 93

let second number be n

product of numbers = product of LCM and HCF

=>12x * x = 93 * n

=>12 * 31 * 31 = 93 * n

=> 11532 /93 = n

=> 124 = n . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (Ans)