The no. of moles of KMnO4 that will be needed to react completely with one mole of ferrous oxalate in acidic solution is
(a) 3/5 (b)2/5
(c)4/5 (d)None of these
A) 3/5......
KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2
KMnO4 = 5 electrons
ferrous oxalate in acidic solution = 3 electrons
while reaction exchange of electrons takes place..........so
3 moles of KMnO4 = 5 moles of FeC2O4
5 moles of FeC2O4 = 3 moles of KMnO4
so 1 mole of FeC2O4 = 3/5 moles of KMnO4
hence 3/5 moles of KMnO4 of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....