The shadow of a tower standing on a level plane is found to be 50m longer when sun's altitude is 300 than when it is 600.Find the height of the tower.

Suppose AB is a tower and its height is 'h'. BC and BD are the lengths of the shadows. such that CD = 50 m.


Using the trigonometry,In triangle ABC,tan 600=ABBC=hBCOr hBC=3or BC=h3and from the triangle ABD,tan 300=ABBD13=hBDOr BD=h3Now,from the diagramBC+CD=BDh3+50=h3h+503=3hor 2h=503or h=253mSo the height of tower=253m

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