the sum of n, 2n,3n terms of A.P. are s1, s2, s3 respectively. prove that s3=3(s2-s1)
Let the first term of the A.P. be a and the common difference be d.
According the question,
We have to prove that S3 = 3 ( S2 – S1).
R.H.S = 3 (S2 – S1)
= S3
= L.H.S
⇒ S3 = 3 ( S2 – S1)