The thermal decomposition of HCO2H is a first order reaction with a rate constant of 2.4 x 10-3 s-1 at a certain temperature.Calculate how long will it take for three-fourths of initial quantity of HCO2H to decompose.
let the rate constant be k = 2.4 x 10-3 s-1
half life of first order reaction is T1/2 = 0.693/k
time taken for three fourths of reaction to take place is two half lives that is 2x T1/2
hence ANS : 2 x 0.693 x 103 / 2.4 seconds = 577.5 seconds