The thermal decomposition of HCO2H is a first order reaction with a rate constant of 2.4 x 10-3 s-1 at a certain temperature.Calculate how long will it take for three-fourths of initial quantity of HCO2H to decompose.

 let the rate constant be k = 2.4 x 10-3  s-1

half life of first order reaction is T1/2 = 0.693/k

time taken for three fourths of reaction to take place is two half lives that is 2x T1/2  

hence ANS : 2 x 0.693 x 103    / 2.4  seconds = 577.5 seconds

  • -6

t=2.303/k log [A0] / [A]

now , since 3/4th is decomposed , so 1/4th of initial is remaining , so [A]=[A0]/4

put it in the equ. & solve.

  • -6
I think so ths is crt

  • 2
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