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the value of cot theta - sin(90-theta)cos(90-theta) is

a)cot theta

b)cos^2 theta

c)cot^2theta

d)cot theta cos^2 theta

 answers of ur queries....

let theta = x

cotx - cosx(sinx)

cosx/sinx - cosxsinx

cosx - cosxsin2x / sinx

cosx ( 1 - sin2x) / sinx

cosx ( cos2x) / sinx

cosx/sinx * cos2x

cotx cos2x

therfore answer d is correct.............

I HOPE U GET IT..........

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View Full Answer

cot theta - cos theta * sin theta                             (sin theta (90-theta) = cos theta and vice versa)

sin theta / cos theta - cos theta * sin theta

by lcm

costheta - cos*sinsquare/sin                          { sinsquare theta = 1-cos square theta}

cos - cos+ cos cube/ sin

cos /sin = cot theta 

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 u see the wrong statement..........

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see the ques.. clearly.. varshith...

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cot θ sin 90 θ cos 90 θ    is:
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