There is number which is greater then the aggregate of its third ,tenth and twelfth parts by 58  CAn u find the number? 

Hi Deeksha!
Here is the answer to your query.
 
Let the number be x
It is given that number is greater than the aggregate of its third, tenth and twelvth parts by 58
 
 
Thus, the number is 120
 
Hope! This will help you.
Cheers!

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 ok f9

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