two charges q1 and q2 are placed at a distance d and the force acting between them is F. If a medim of dielectric constant 4 is introduced arond them, the force now will be
- 4F
- 2F
- F/2
- F/4
Force between the two charge particles is given by:
o i s t h e a b s o l u t e p e r m i t i v i t y o f t h e v a c u u m .
w h e n a n d i e l e c t r i c m a t e r i a l o f c o n s tan t k i s i n t r o d u c e d i n b e t w e e n ,
F' = F/4
So force is reduced by 1/4 of the initial value.
F' = F/4
So force is reduced by 1/4 of the initial value.