. Two identical resistors each of resistance 10 ohm are connected : (i) in series and (ii) in parallel, in turn to a battery of 6V. calculate the ratio of power consumed in the combination of resistors in the two cases

case 1: when the resistance is connected in series

then the total resistance is 10 + 10 = 20 ohm and the given voltage is 6 volt

then acc. to the formula I = V/R we find that the current is 0.3 A

case 2: when the resistance is connected in parallel

again applying the formula...I= V/R we find that the current is 1.2 A

now let the current in series connection be I1 and in the parallel connection be I2

volttage is same in both the cases

we know that P = VI , 

taking out the ratio of both the cases appyling the above formula,we get

6 * 0.3 / 6 * 1.2

we get, 1/4,therefore the ratio is 1:4

 Draw the circuit diagram of the two cases

• first case 

• first case
• 

•  second case

 in the first how it is  1.2 A when the resistance is connected in parallel

again applying the formula...I= V/R we find that the current is and what will be the value of V and R