two stones are thrown up simultaneously with their initial velocities U1 and U2 respectively prove that the heights reached - Science - Motion

Question

two stones are thrown up simultaneously with their initial
velocities U1 and U2 respectively prove that the heights reached
them would be in the ratio of V1 :V2

Kranav Sharma · Accepted Answer

Suppose the two stones are A and B

For A,

${v_{1}}^{2} = {u_{1}}^{2} + 2 g h_{1} 0 = {u_{1}}^{2} + 2 � (- 9.8) h_{1} h_{1} = {u_{1}}^{2} / (2 � 9.8) - - (i) F o r &InvisibleTimes B, {v_{2}}^{2} = {u_{2}}^{2} + 2 g h_{2} 0 = {u_{2}}^{2} + 2 � (- 9.8) h_{2} h_{2} = {u_{2}}^{2} / (2 � 9.8) - - (i i) D i v i d i n g &InvisibleTimes (i) b y &InvisibleTimes (i i), w e &InvisibleTimes g e t \frac{h_{1}}{h_{2}} = \frac{{u_{1}}^{2}}{{u_{2}}^{2}}$

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two stones are thrown up simultaneously with their initial velocities U1 and U2 respectively. prove that the heights reached them would be in the ratio of V1 :V2