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Vivek Raipat from Jawahar Vidya Mandir, asked a question
Subject: Science , asked on 3/9/11

 What is net displacement?

EXPERT ANSWER

Ruhhi Ralhan , Meritnation Expert added an answer, on 9/9/11
773 helpful votes in Science
Hi,

@All, Right answer. Keep up this good effort!
@ Vivek, hope you got the answer.


This conversation is already closed by Expert

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Abhaya Senapati , added an answer, on 3/9/11
1 helpful votes in Science

The shortest distance bet d initial point and final point

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555 555 From 2222jjd Rawanpoorr, added an answer, on 3/9/11
2 helpful votes in Science

the smallest distance betweenthe start point to end point only in a straight line

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Jackie Jain From The Banyan Tree School, added an answer, on 3/9/11
83 helpful votes in Science

 Net displacement is the distance of a straight line from the beginning point to the end point. 

You can walk what would be a straight path of 2 km or a 12 km scenic path and both lead to the same point. You decide to take the scenic route and walk for 12 km to your destination. 

Your net displacement is only 2 km even though you chose to walk the 12 km path, because it 's the shortest distance between the start and finish points.

To solve this problem it looks like you 're going to have to find the hypotenuse of a triangle. If you draw the paths on a sheet of paper you can draw a straight line north from where he started 40 m distant.

Next you can draw a diagonal line at an angle toward where he ended his run from the beginning point.

Now the right triangle becomes as follows.

Hypotenuse = x

Side a = 40 m 

Side b = 20 m

So to find our displacement we use 

C^2 = A^2 + B^2

C^2 = 40m^2 + 20m^2

C^2 = 1600m^2 + 400m^2

C = sr(2000m^2) sr = square root

C = 44.72m Total displacement 

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