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what is the formula of (a-b) whole cube?
(a-b)^{3} = a^{3 }- 3a^{2}b + 3ab^{2} -b^{3}
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(a-b)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3}
(a-b)^{3}= a^{3}-3a^{2}b+3ab^{2}-b^{3}
but what is (a+b) whole cube
(a+b)^{3} = a^{3} +b^{3}+3a^{2}b +3ab^{2}
(a+b)3 (a-b)3
(a)6+12b4
(-a-b)^{3} =========? plz helpppp
(a+b)3 = a3 + 3a2b +3ab2 + b3
- (a+b)3 = - (a3 + 3a2b +3ab2 + b3)
therefore, (-a-b)3 = -a3 - 3a2b - 3ab2 - b3 -bro.....hop tizz helps bt try nt 2 rest ur brain
very gd
demag kharab ha ap sab ka
yaar kyu paka rahe ho
a3-b3-3ab(a-b)
a^3-3a^2b+3ab^2-b^3
a^{3}-3a^{2}b+3ab^{2}-b^{3}
a3-b3+2a
(a-b) ^{3} = a ^{3 } - 3a ^{2} b + 3ab ^{2} -b ^{3}
(a-b)^{3 }= (a-b) (a-b)^{2} =(a-b) ( a^{2 }+ b^{2} -2ab) = a(a^{2} + b^{2} - 2ab) -b (a^{2} +b^{2} -2ab) =
a3-b3+3ab(a-b)
(a-b) = a^{3}-3a^{2}b+3ab^{2}-b^{3}
aaaa !!! xamz khatm ho gaye kya???
please vote or ...
hello
^{what is the whole cube of two rootover two and x} ^{3}
1
[a-b]=a3 -3a2+3ab2-b2
(a-b)^{3}=a^{3}-b^{3}-3ab(a-b)
(a-b)^{3 } = (a)^{3}+ (-b)^{3}-3*a*b*(a-b)
= a^{3} -b^{3} -3a^{2}b +3ab^{2}
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