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What is the Van't Hoff Factor in  K4[Fe(CN)6] and BaCl2 ? AND How it is calculated here ?

Asked by asonianj2011...(student) , on 28/1/12


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EXPERT ANSWER

Von’t Hoff factor may be defined as

  =

When K4[Fe(CN)6] dissociate, it gives four K+ ion and one [Fe(CN)6]4- ion therefore Von’t Hoff factor is 5/1 = 5

Similarly for BaCl2, Von’t Hoff factor is 3

Posted by Chandra Prakash(MeritNation Expert)on 29/1/12

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YES CORRECT BY APPLYING 1+(N-1)ALPHA , WHERE APLHA IS DEGREE OF DISSOCIATION .

IT IS 5 AND 3 RESP.

Posted by . .(teacher)on 29/1/12

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