What is the Van't Hoff Factor in K4[Fe(CN)6] and BaCl2 ? AND How it is calculated here ?
Von’t Hoff factor may be defined as
When K4[Fe(CN)6] dissociate, it gives four K+ ion and one [Fe(CN)6]4- ion therefore Von’t Hoff factor is 5/1 = 5
Similarly for BaCl2, Von’t Hoff factor is 3
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YES CORRECT BY APPLYING 1+(N-1)ALPHA , WHERE APLHA IS DEGREE OF DISSOCIATION .
IT IS 5 AND 3 RESP.
K4 [Fe(CN)6] , i=5
BaCl2 = 3
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