Purchase mobileappIcon Download our Mobile App
Call Us at 011-40705070  or  
Click to Call
Select your Board & Class
  • Select Board
  • Select Class

What is the Van't Hoff Factor in  K4[Fe(CN)6] and BaCl2 ? AND How it is calculated here ?

Asked by asonianj2011...(student) , on 28/1/12


Become Expert
Become a Chemistry expert
Start Now with Video Lessons, Sample Papers, Revision Notes & more for Class-XII-Science - CBSE 

EXPERT ANSWER

Von’t Hoff factor may be defined as

  =

When K4[Fe(CN)6] dissociate, it gives four K+ ion and one [Fe(CN)6]4- ion therefore Von’t Hoff factor is 5/1 = 5

Similarly for BaCl2, Von’t Hoff factor is 3

Posted by cp_gupta17...on 29/1/12

This conversation is already closed by Expert

More Answers

YES CORRECT BY APPLYING 1+(N-1)ALPHA , WHERE APLHA IS DEGREE OF DISSOCIATION .

IT IS 5 AND 3 RESP.

Posted by . .(teacher)on 29/1/12

Ask a QuestionHave a doubt? Ask our expert and get quick answers.
Show me more questions

close