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asonianj2011... , asked a question
Subject: Chemistry , asked on 28/1/12

What is the Van't Hoff Factor in  K4[Fe(CN)6] and BaCl2 ? AND How it is calculated here ?

EXPERT ANSWER

Chandra Prakash ,Meritnation Expert added an answer
Answered on 29/1/12

Von’t Hoff factor may be defined as

  =

When K4[Fe(CN)6] dissociate, it gives four K+ ion and one [Fe(CN)6]4- ion therefore Von’t Hoff factor is 5/1 = 5

Similarly for BaCl2, Von’t Hoff factor is 3

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asonianj2011... , added an answer
Answered on 29/1/12

K4 [Fe(CN)6] , i=5

BaCl2 = 3

. . , From Manav Mangal School, Panchkula,sector-11 , added an answer
Answered on 29/1/12

YES CORRECT BY APPLYING 1+(N-1)ALPHA , WHERE APLHA IS DEGREE OF DISSOCIATION .

IT IS 5 AND 3 RESP.