When ammonia is treated with O2 at elevated temperatures, the rate pf disappearance of ammonia is found to be 3.5x 10 to the power -2 mol/dm s during a measured time interval. Calculate the rate of appearance of nitric oxide and water ?
d[H2O]/dtThe balanced chemical equation showing diappearance of ammonia is as follows:
4NH3 + 5 O2 → 4NO + 6 H2O
Rate of reaction ,
-1/4d[NH3]/dt = -1/5d[O2]/dt = 1/4d[NO]/dt = 1/6d[H2O]/dt
Rate of disappearance of ammonia = Rate of appearance of NO = 3.5 x 10-2 mol dm3 s-1
rate of appearance of water is 1/6d[H2O]/dt = 1/4d[NO]/dt
Given that Rate of appearance of NO = 3.5 x 10-2 mol dm3 s-1
d[NO]/dt = 3.5 x 10-2 mol dm3 s-1/ 4 = 8.75 x 10-3 mol dm3 s-1
d[H2O]/dt = 6 x 3.5 x 10-2 mol dm3 s-1/ 4 = 5.25 x 10-2 mol dm3 s-1
4NH3 + 5 O2 → 4NO + 6 H2O
Rate of reaction ,
-1/4d[NH3]/dt = -1/5d[O2]/dt = 1/4d[NO]/dt = 1/6d[H2O]/dt
Rate of disappearance of ammonia = Rate of appearance of NO = 3.5 x 10-2 mol dm3 s-1
rate of appearance of water is 1/6d[H2O]/dt = 1/4d[NO]/dt
Given that Rate of appearance of NO = 3.5 x 10-2 mol dm3 s-1
d[NO]/dt = 3.5 x 10-2 mol dm3 s-1/ 4 = 8.75 x 10-3 mol dm3 s-1
d[H2O]/dt = 6 x 3.5 x 10-2 mol dm3 s-1/ 4 = 5.25 x 10-2 mol dm3 s-1