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which term of A.P 121,117,113...is the first negative term?

The answer posted by Astershines is correct.

The missing symbol is ×.

@Astershines: Well done. Keep up the hard work.

  • -3
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The given A.P is 121, 117, 113…
Here, first term a = 121 and common difference, d = –4.
Let nth term be the first negative term of the given A.P
∴ an < 0
⇒ 121 + (n – 1) × (–4) < 0  (an = a + (n – 1) d)
⇒ –4n + 125 < 0
⇒ – 4n < – 125
∴ n = 32  [Since n is a natural number]
 
Thus, 32nd term is the first negative term of the given A.P.
 
Cheers!
HOPE THIS HELPS!!PLS GV THUMBS UP F U LYK!!:):)
  • 47

a=121   d=-4

a+(n-1)d <0

121 + (n-1)(-4) <0

n-1<-121/-4

n-1<30.25

n<31.25

n=31 

 

thumbs up.

  • 1

sorry

n-1>121/4

n-1>30.25

n>31.25

n=32

  • 3
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