why are axial bonds longer than equatorial in pcl5... sp3d hybridisation??

The difference in bond length is due to repulsive forces from electron pairs at other bond angle.

In PCl5 there are electron pairs at 2 axial and 3 equatorial bonds.

The e- pair at equatorial position are at an angle of 1200 from other two e- pairs at equatorial positions and 90o from the 2 pairs of e- at axial position. Thus it suffers repulsive forces from 2 e- pair at 900 and two at 1200.

The e- pair at axial position is repelled by three e- pair at 900 that are at equatorial position and 1 e- pair at 1800 which is at other axial end.

Repulsive force decreases with increase in bond angle. The repulsive force from 1200 and 1800 bond angle is almost negligible. So the axial position has 3 repulsions from 900 and equatorial has 2 repulsion from 900. As axial is repelled more it gets farther and the bond length increases.

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Understood any of this???????

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nopes...............

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but wow!!!!! wat xplanation.. wowowow

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 good answer.

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then why in  IF7 repulsion is symmetrical?

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 it is due to bonfdpair and lone pair repulsions. 

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can u plz simplify this answer
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plz do soon i hv my exam tomorrow
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I am sorry...if I am late...but..to put it in simple words, there are 5 bonds in the trigonal bipyramidal arrangement...where 3 are equatorial bonds...having an angle of 120° between them..and 2 are axial bonds..which have an angle of 90° with the equatorial bonds. Now...if we take one of the equatorial bonds into consideration, it suffers 2 90° repulsions with the axial bonds..one above n one below its plane..However..in the case of an axial bond...it suffers 3 90° repulsions..with each of the equatorial bonds. Thus, since they suffer more repulsions, the axial bonds are slightly longer than the equatorial bonds. It is just the same thing that she had said..except I think I have made it simpler for you.. Hope you understood..😊
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........q
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lllllll
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