Purchase mobileappIcon Download our Mobile App
Call Us at 011-40705070   or  
Click to Call
Select your Board & Class
  • Select Board
  • Select Class

WHY DOES A RAY OF LIGHT PASSING THROUGH THE CENTRE OF CURVATURE OF A CONCAVE MIRROR AFTER REFLECTION, IS REFLECTED BACK ALONG THE SAME PATH???

Asked by Nimmy Roy(student) , on 1/12/12

Answers

badges

......because the incident rays fall on the mirror along the normal to the reflecting surface.

Good luck!!

Posted by Aish Allada(student)on 12/3/12

badges

A ray of light passing through the centre of curvature of a concave mirror gets reflected along the same path because when ray of light passes through centre of curvature of a concave mirrorit strikes the mirror at 90 degree that is incident ray coincides normal therefore angle of incidence = 0 so, according to law of reflection angle of reflection = 0 thus ray of light retraces its path.

or

when the ray passes throughthe center of curvature....on the mirror it falls perpendicularrly...ie.it coincides wid normal on the piint of incidence......

according to the lawsof reflection...angle of ( incidence=reflection.)

thus applyinn this rule..if the incident ray coincides wid normal thus its distance angle 4rm it is 0o thus agle f reflection is also...0o n the reflected ray bounces back...!! hope this helps..:))

Posted by Bluestar(student)on 12/3/12

For concave and convex GLASS

wen ray of light strikes at 90 degrees on a two side parallel glass(in this case it is d center of curvature) it passes through it undeviated......

Posted by Suharsh Tyagi(student)on 12/3/12

badges

as other side is opaque, it is reflected back

Posted by Nagesh Moholkar(student)on 2/12/12

Ask a QuestionHave a doubt? Ask our expert and get quick answers.
Show me more questions

close