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WHY DOES A RAY OF LIGHT PASSING THROUGH THE CENTRE OF CURVATURE OF A CONCAVE MIRROR AFTER REFLECTION, IS REFLECTED BACK ALONG THE SAME PATH???

Asked by Nimmy Roy(student) , on 1/12/12

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 ......because the incident rays fall on the mirror along the normal to the reflecting surface.

Good luck!!

Posted by Aish Allada(student)on 12/3/12

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 A ray of light passing through the centre of curvature of a concave mirror gets reflected along the same path because when ray of light passes through centre of curvature of a concave mirror it strikes the mirror at 90 degree that is incident ray coincides normal therefore angle of incidence = 0  so, according to law of reflection angle of reflection = 0 thus ray of light retraces its path.

 or

when  the  ray  passes  throughthe  center of curvature....on  the  mirror  it  falls  perpendicularrly...ie.it  coincides  wid  normal  on  the  piint  of  incidence......

according  to the  lawsof  reflection...angle of ( incidence=reflection.)

thus  applyinn  this  rule..if  the  incident  ray  coincides  wid  normal thus  its  distance  angle  4rm  it  is  0o  thus  agle  f  reflection  is  also...0o  n  the  reflected  ray  bounces  back...!!  hope  this  helps..:))

Posted by Bluestar(student)on 12/3/12

For concave and convex GLASS

wen ray of light strikes at 90 degrees on a two side parallel glass(in this case it is d center of curvature) it passes through it undeviated......

Posted by Suharsh Tyagi(student)on 12/3/12

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as other side is opaque, it is reflected back

Posted by Nagesh Moholkar(student)on 2/12/12

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