without actually calculating the cubes find the value of cube of 27 + cube of -14 + cube of -13 .
please answer with detailed explanations
273+(-14)3+(-13)3
Let a=27, b=(-14) and c=(-13)
if a+b+c=0 so a3+b3+c3=3abc
27+(-14)+(-13)=27-27=0
here a+b+c=0
so, a3+b3+c3=3abc
3abc=3*27*(-14)*(-13)
=14742
Hope ur satisfied wid ur answer :D
Let a=27, b=(-14) and c=(-13)
if a+b+c=0 so a3+b3+c3=3abc
27+(-14)+(-13)=27-27=0
here a+b+c=0
so, a3+b3+c3=3abc
3abc=3*27*(-14)*(-13)
=14742
Hope ur satisfied wid ur answer :D