The sum of ages of a father and his son is 45 year. 5 years ago, the product of their ages (in years) was 124. Determine their present ages.
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Let the present age of son be x years and 5 years ago his age be x-5 years
Father’s age | Son’s age | |
Present age | 45-x years | X years |
5 years ago | 40-x years | x-5 years |
40-x(x-5)=124
40-x(x-5)=124
40x-x2-200+5x=124
-x2+45x-200-124=0
X2-45x+324=0
(sum=-45,product=324)
X2-36x-9x+324=0
X(x-36)-9(x-36)=0
x-9=0 (or)x-36=0
x=9 (or)
x=36 (not possible)
x=9
Then 45-x
=45-9
36
The present age of father is 36 years and the present age of son is 9 years