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njsheth27... asked this question on Class X » Math

sum of squares of three consecutive positive even integer is 200,while their mean is 2(x+1).

Asked by njsheth27...(student), on 27/4/12
Answers

Let first positive even integer=x

So second consecutive even integer= x+2

Third consecutive even integer= x+4

x2+(x+2)2+(x+4)2=200

x2+x2+4x+4+x2+8x+16=200

3x2+12x+20=200

3x2+12x-180=0

x2+4x-60=0

x2+10x-6x-60=0

x(x+10)-6(x+10)=0

(x-6)(x+10)=0

x=6, x=-10

x= -10 cannot be the value of x since the integers are positive

so the three consecutive even integers are 6,8 & 10

Posted by viky79(tutor), on 8/5/12

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