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sulaksh asked this question on Class X » Math » Triangles

In a trapezium ABCD, AB is parallel to DC  and DC = 2AB E is point on BC such that BE : EC = 3:4. EF is drawn parallel to AB where F is a point on AD . Prove that 7EF = 10AB.

Asked by sulaksh(student), on 10/3/10
Answers

Join D and B by a diagonal and use the BPT You will get the answer

Posted by NITIN(student), on 10/3/10

Nitin , can you please give the solution

Posted by arty2494(student), on 10/3/10

 it is in rd sharma

Posted by Akhila-Sadanandan(student), on 10/3/10
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