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riaharshchittra asked this question on Class X » Science » Electricity

A wire of resistance 9 ohm is bent in a form of equilateral triangle. the equivalent resistance between any two of its vertices will be

Let ABC be the equilateral triangle formed. AB = BC = CA = L (say)

The original length of the wire = 3L, whose resistance is 9 Ω.

Since, resistance is directly proportional to the length, so each side of the triangle have equal resistance.

That is, RAB = RAC = RCA = 3 Ω

Let us find the resistance across A and B.

RAC and RBC are in series, so, they have a combined resistance of 3+3 = 6 Ω

This 6 Ω is in parallel with RAB. So the equivalent resistance across A and B is, Req = (6×3)/(6+3) = 2 Ω.

Posted by Somnath Mazumder (MeritNation Expert), on 23/6/12
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