explain componendo and dividendo....
Componendo and dividendo is a method of simplification in mathematics. According to it, This proof is invalid for a=b and c=d because if such that a = b & d = c then by application of componendo and dividendo we get {a=b,c=d} and since division by zero is not defined :
According to it,
This proof is invalid for a=b and c=d because if
then by application of componendo and dividendo we get {a=b,c=d} and since division by zero is not defined :
plzzzzzzzzzzzzz thumbs up
omponendo and dividendo is a fundamental concept in mathematics. It helps in solving complex problems. if a / b = c / d , then by applying componendo and dividendo , we get (a + b) / ( a - b ) = (c + d ) / ( c - d ), where a is not equal to b. This proof is invalid for a = b and c= d . because if a/b = c/d and a = b and c= d / then ( a+ b ) / ( a - b ) = ( c + d ) / ( c- d ) (a+b ) / 0 = ( c+d) / 0 which is not defined. componendo and dividendo is a combination of componendo and dividendo. Proof of Componendo and Dividendo Rule componendo rule proof If a / b = c / d, then by using componendo , we get , ( a + b ) / b = ( c + d ) / d Proof: adding 1 both side , we get a / b + 1 = c / d + 1 ( a + b ) / b = ( c + d ) / d hence proved. Proof of dividendo rule If a / b = c / d , then ( a - b ) / b = ( c - d ) / d proof: subtracting 1 from both side , we get a / b - 1 = c / d - 1 ( a - b ) / b = ( c - d ) / d hence proved. Proof of Componendo and Dividendo if a / b = c / d , then ( a + b ) / ( a - b ) = ( c + d ) / ( c - d ) proof : Taking L. H . S, we get ( a + b ) / ( a - b ) = ( a / b + 1 ) / ( a / b - 1 ) = ( c / d + 1 ) / ( c / d - 1 ) = ( c + d ) / ( c - d ) Hence proved.
if a / b = c / d , then by applying componendo and dividendo , we get
(a + b) / ( a - b ) = (c + d ) / ( c - d ), where a is not equal to b.
This proof is invalid for a = b and c= d .
because if a/b = c/d and a = b and c= d / then ( a+ b ) / ( a - b ) = ( c + d ) / ( c- d )
(a+b ) / 0 = ( c+d) / 0
which is not defined.
componendo and dividendo is a combination of componendo and dividendo.
componendo rule proof
If a / b = c / d,
then by using componendo , we get ,
( a + b ) / b = ( c + d ) / d
Proof:
adding 1 both side , we get
a / b + 1 = c / d + 1
hence proved.
Proof of dividendo rule
If a / b = c / d , then ( a - b ) / b = ( c - d ) / d
proof:
subtracting 1 from both side , we get
a / b - 1 = c / d - 1
( a - b ) / b = ( c - d ) / d
if a / b = c / d , then ( a + b ) / ( a - b ) = ( c + d ) / ( c - d )
proof :
Taking L. H . S, we get ( a + b ) / ( a - b ) = ( a / b + 1 ) / ( a / b - 1 ) = ( c / d + 1 ) / ( c / d - 1 )
= ( c + d ) / ( c - d )
Hence proved.
plzzzzzzzz thumbs up
k
ur effort is really appreciable.
its all copy paste from wikipedia. we can go on it u knw
3a + 2x=2a+ 9x
according to divindo and componendo rule
a/b=c/d converts into a+b/a-b=c+d/c-d