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Shivani Patil
Subject: Maths
, asked on 7/2/18
Quadrilateral ABCD and PBQR are parallelogram such that AQ parallel to CP and AQ parallel to QR. Show that A(parallelogram ABCD)=A(parallelogram PBQR)
Answer
1
Ujjwal
Subject: Maths
, asked on 3/2/18
Q
. P,Q,R and S are mid-points of AB, BC, CD and Ad of a quadrilateral ABCD. Prove that ABCD is a parallelogram and area of parallelogram PQRS =
1
2
area of quadrilateral ABCD.
Answer
1
Advait.n
Subject: Maths
, asked on 3/2/18
how do we get to know when to make a cunstruction and where to make it
Answer
1
Advait.n
Subject: Maths
, asked on 3/2/18
If D is the mid .point of side of side BC of a ΔABC, P and Q are two points lying respectively on the sides AB and BC such that DP is parallel to QA. Prove that ar(ΔCQP) = 1/2 ar(ΔABC).
Answer
1
Gagandeep Singh
Subject: Maths
, asked on 1/2/18
Q. ​ABCD is a quadrilateral, BE||AC meeting DC produced at E. ar (
△
ADC) = 10
c
m
2
, ar (
△
ABC) 7
c
m
2
, find ar (
△
ADE).
Answer
1
Suvam
Subject: Maths
, asked on 23/1/18
Q
4
.
I
n
t
h
e
f
i
g
u
r
e
,
a
r
e
a
o
f
△
A
B
C
=
27
c
m
2
a
n
d
E
F
∥
B
C
.
F
i
n
d
t
h
e
a
r
e
a
o
f
p
a
r
a
l
l
e
log
r
a
m
A
B
C
F
.
A
12
c
m
2
B
60
c
m
2
C
54
c
m
2
D
36
c
m
2
Answer
1
Tejas Goyal
Subject: Maths
, asked on 19/1/18
Question 16
Answer
1
Yash Pratap Singh
Subject: Maths
, asked on 18/1/18
In a triangle ABC,E is the mid-point of median AD. Show that ar.(BED) = 1\4 ar.(ABC)?
Answer
2
Tejas Goyal
Subject: Maths
, asked on 15/1/18
Question19
Answer
1
Tejas Goyal
Subject: Maths
, asked on 15/1/18
Question18
Answer
1
Tejas Goyal
Subject: Maths
, asked on 15/1/18
Q
17
.
A
B
C
D
i
s
a
∥
g
r
m
i
n
w
h
i
c
h
B
C
i
s
p
r
o
d
u
c
e
t
o
E
s
u
c
h
t
h
a
t
C
E
=
B
C
.
A
E
i
n
t
e
r
s
e
c
t
C
D
a
t
F
.
Answer
1
Tejas Goyal
Subject: Maths
, asked on 15/1/18
Question2
Answer
1
Tejas Goyal
Subject: Maths
, asked on 15/1/18
Question1
Answer
1
Fareeha Rahman
Subject: Maths
, asked on 13/1/18
Diagonals AB and BD of quadrilateral ABCD intersect each other at P. Show that area of APB X Area of CPD = Area of ABC X Area of BPC
Answer
1
Shivani Patil
Subject: Maths
, asked on 13/1/18
In the figure ABC is a right angled triangle at A BCED, ACFG,ABMN are squares on the side BC,CA,AB respectively line segment AX perpendicular to DE meets BC at Y show that : triangle MBC Congruent to triangle ABD 2. Area (BYXD) = 2* Area ( Triangle MBC) 3. Area ( triangle FCB) congruent ( Triangle ACE) 4 . Area(CYXE)= 2 Area triangle FCB 5. Area( CYXE)=Area(ACFG) 6. Area (BCED)= Area(ABMN)+Area (ACFG)
Answer
3
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Q. ​ABCD is a quadrilateral, BE||AC meeting DC produced at E. ar (ADC) = 10 , ar (ABC) 7, find ar (ADE).