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Champ Jee
Subject: Maths
, asked on 21/5/18
Ans: option (a).
But ?x^2 = mod x. Then, how can it be negative.
It should be option c, isn't it?
Q67. The value of
log
0
.
5
2
4
, is
(a) – 2 (b)
-
4
(c) 2 (d) none of these
[CEF (Delhi) 2002]
Answer
1
Subhojit Roy
Subject: Maths
, asked on 1/5/18
please answer fast.
Q.24. Solve : (a > 0)
2
log
x
a
+
log
a
x
a
+
3
log
a
2
x
a
=
0
Answer
1
Lavneesh Rajput
Subject: Maths
, asked on 18/4/18
Solve this:
171.
The total number of ways of selecting six coins out of 20 one rupee coins, 10 fifty paise coins and 7 twenty five paise coins is
(
a
)
C
6
37
(
b
)
56
(
c
)
28
(
d
)
29
Answer
1
Amitesh Kumar
Subject: Maths
, asked on 14/4/18
If the sum of the coefficient in the expansion of
1
-
3
x
+
10
x
2
n
is
a
and if the sum of the coefficients in the expansion of (1 +
x
2
)
n
is
b
, then :
(1)
a
= 3
b
(2)
a
=
b
3
(c)
b =
a
3
(4) None of these
Answer
1
Amitesh Kumar
Subject: Maths
, asked on 14/4/18
If the last term in the binomial expansion of
(
2
1
3
-
1
2
)
n
i
s
(
1
3
5
3
)
log
3
8
, then the 5th term from the beginning is
(1) 210
(2) 420
(3) 105
(4) none of these
Answer
1
Dharmveer Gautam
Subject: Maths
, asked on 10/4/18
Please solve last 2 question in detail.
Q.13. Show that
9
n
+
1
-
8
n
-
9
is divisible by 64, whenever n is a positive integer.
Q.14. Prove that
∑
r
=
0
n
3
r
C
r
n
=
4
n
.
Answer
1
Bhavi Sibal
Subject: Maths
, asked on 5/4/18
I
f
ω
≠
1
i
s
a
c
u
b
e
r
o
o
t
o
f
u
n
i
t
y
a
n
d
ω
+
x
n
=
1
+
12
ω
+
69
ω
+
.
.
.
.
t
h
e
n
t
h
e
v
a
l
u
e
s
o
f
n
a
n
d
x
a
r
e
r
e
s
p
e
c
t
i
v
e
l
y
(
A
)
36
,
1
(
B
)
12
,
2
(
C
)
24
,
1
/
2
(
D
)
18
,
1
/
3
Answer
1
Bhavi Sibal
Subject: Maths
, asked on 5/4/18
Q5. The degree of expression
x
+
x
3
-
1
1
2
5
+
x
-
x
3
-
1
1
2
5
is
(A) 5
(B) 6
(C) 7
(D) 8
Answer
1
Bhavi Sibal
Subject: Maths
, asked on 4/4/18
21?
21
.
I
f
t
h
e
4
t
h
t
e
r
m
s
i
n
t
h
e
e
x
p
a
n
s
i
o
n
o
f
p
x
+
x
-
1
m
i
s
2
.
5
f
o
r
a
l
l
x
∈
R
,
t
h
e
n
a
p
=
5
2
,
m
=
3
(
b
)
p
=
1
2
,
m
=
6
(
c
)
p
=
-
1
2
,
m
=
6
(
d
)
n
o
n
e
o
f
t
h
e
s
e
Answer
1
Bhavi Sibal
Subject: Maths
, asked on 4/4/18
20?
20. If the coefficient of 4
th
term in the expansion of
x
+
α
2
x
n
i
s
20
.
t
h
e
n
t
h
e
r
e
s
p
e
c
t
i
v
e
v
a
l
u
e
s
o
f
α
a
n
d
n
a
r
e
a) 2,7 b) 5,8 c) 3,6 d) 2,6
20 ?
Answer
1
Amitesh Kumar
Subject: Maths
, asked on 26/3/18
T
h
e
s
u
m
∑
r
=
1
n
r
C
r
2
n
i
s
e
q
u
a
l
t
o
(
A
)
n
.
2
2
n
-
1
(
B
)
2
2
n
-
1
(
C
)
2
n
-
1
+
1
(
D
)
N
o
n
e
o
f
t
h
e
s
e
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 23/3/18
Plz ans soon..
36. Verify by the method of contradiction that
17
is irrational
Answer
1
Yagyam Aggarwal
Subject: Maths
, asked on 18/3/18
Please answer 80 th question
80.
The value of
5
log
7
11
-
11
log
7
5
i
s
(1) 0 (2) 5
(3) 7 (4) 11
Answer
1
Sananda.s
Subject: Maths
, asked on 13/3/18
Q. If P be the sum of odd terms and Q that of even terms in the expansion of
x
+
a
n
, prove that
(
i
)
P
2
-
Q
2
=
x
2
-
a
2
n
(
i
i
)
4
P
Q
=
x
+
a
2
n
-
x
-
a
2
n
(
i
i
i
)
2
P
2
+
Q
2
=
x
+
a
2
n
+
x
-
a
2
n
Answer
1
Drishti
Subject: Maths
, asked on 6/3/18
Solve ques(find theseventh ,......)
Answer
1
1
2
3
4
5
Next
What are you looking for?
But ?x^2 = mod x. Then, how can it be negative.
It should be option c, isn't it?
Q67. The value of , is
(a) – 2 (b) (c) 2 (d) none of these
[CEF (Delhi) 2002]
Q.24. Solve : (a > 0)
171. The total number of ways of selecting six coins out of 20 one rupee coins, 10 fifty paise coins and 7 twenty five paise coins is
(1) a = 3b (2) a = b3 (c) b = a3 (4) None of these
, then the 5th term from the beginning is
Q.13. Show that is divisible by 64, whenever n is a positive integer.
Q.14. Prove that .
(A) 5
(B) 6
(C) 7
(D) 8
20. If the coefficient of 4th term in the expansion of
a) 2,7 b) 5,8 c) 3,6 d) 2,6 20 ?
36. Verify by the method of contradiction that is irrational
80. The value of
(1) 0 (2) 5
(3) 7 (4) 11
Q. If P be the sum of odd terms and Q that of even terms in the expansion of, prove that