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Akanksha Prasad
Subject: Chemistry
, asked on 13/8/19
Please solve question-H
Answer
1
Akanksha Prasad
Subject: Chemistry
, asked on 13/8/19
Please solve question-F
Answer
1
Champ Jee
Subject: Chemistry
, asked on 27/7/19
Kindly explain the chemistry of this question.
30. The enthalpy of neutralization of a weak monoprotic acid (H
A
) in 1
M
solution with a strong base is –55.95 kJ/mol. If the unionized acid required 1.4 kJ/mol heat for its complete ionization and enthalpy of neutralization of the strong monobasic acid with a strong monoacidic base is –57.3 kJ/mol, what is the % ionization of the weak acid in molar solution
(a) 1%
(b) 3.57%
(c) 35.7%
(d) 10%
Answer
1
Champ Jee
Subject: Chemistry
, asked on 11/7/19
Q30.
Ans: 6.
The word equivalent has confused me.
Answer
1
Champ Jee
Subject: Chemistry
, asked on 11/7/19
Q2.
Ans: 3.502 kJ.
2. For the reaction : 2A (g) + 3B (g)
→
4C (g) + D (
l
) ; ∆H = –20 KJ/mole
Find the heat exchanged when 0.4 mole of A reacts with excess of B in a closed rigid container. The temperature is constant at 300 K. [R = 8.3 J/K mole]
Answer
1
Champ Jee
Subject: Chemistry
, asked on 4/7/19
34. p-cresol reacts with chloroform in alkaline medium to give the compound A which adds hydrogen cyanide to form, the compound. B The latter on acidic hydrolysis gives chiral carboxylic acid. The structure of the carboxylic acid is-
Answer
1
Champ Jee
Subject: Chemistry
, asked on 2/7/19
Ques in pic.
Ans: B
Getting 3.5
A nitrogen-hydrogen mixture initially in the molar ratio of 1 : 3 reached equilibrium to form ammonia when 25% of the N
2
and H
2
had reacted. If the total pressure of the system was 21 atm, the partial pressure of ammonia at the equilibrium was:
(a) 4.5 atm
(b) 3.0 atm
(c) 2.0 atm
(d) 1.5 atm
Answer
1
Champ Jee
Subject: Chemistry
, asked on 9/6/19
Q31.
Ans: A.
How?
(A) Enantiomer
(B) Diastereomers
(C) Meso
(D) Achiral
Answer
1
Champ Jee
Subject: Chemistry
, asked on 6/6/19
Q20.
Ans: C.
Explain thru a mechanism.
20.
CH
3
-
CH
2
-
CH
2
-
Br
+
CH
3
3
CO
-
→
CH
3
3
COH
50
°
C
(A) CH
3
– CH
2
– CH
3
& SN
2
(B) CH
3
– CH = CH
2
& SN
1
(C) CH
3
– CH = CH
2
& E
2
(D) None
Answer
1
Champ Jee
Subject: Chemistry
, asked on 19/5/19
Q5.
Ans: C.
Explant pls asap
Q5. For a reaction, 2X(s) + 2Y(s) → 2C(
l
) + D(g)
The
q
p
at 27°C is –28 kcal mol
–1
, the q
v
is ________ Kcal mol
–1
(A) –27.4
(B) +27.4
(C) –28.6
(D) 28.6
Answer
1
Champ Jee
Subject: Chemistry
, asked on 24/3/19
Q43.
Help asap!
Answer
1
Kk Hardy
Subject: Chemistry
, asked on 5/3/19
Experts please help.....
The volume of one mole ideal monatomic gas at temperature T on an adiabatic flask is increased from 1 to 2 litre at an external pressure of 1atm. Determine the final temperature......
Answer
1
Champ Jee
Subject: Chemistry
, asked on 20/2/19
Q24.
Ans: bcd.
Exain B and D.
Answer
1
Champ Jee
Subject: Chemistry
, asked on 20/2/19
Q30.
Ans: b
How?
Answer
1
Champ Jee
Subject: Chemistry
, asked on 19/2/19
Q2.
Ans: B.
How?
Answer
1
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What are you looking for?
30. The enthalpy of neutralization of a weak monoprotic acid (HA) in 1 M solution with a strong base is –55.95 kJ/mol. If the unionized acid required 1.4 kJ/mol heat for its complete ionization and enthalpy of neutralization of the strong monobasic acid with a strong monoacidic base is –57.3 kJ/mol, what is the % ionization of the weak acid in molar solution
(a) 1%
(b) 3.57%
(c) 35.7%
(d) 10%
Ans: 6.
The word equivalent has confused me.
Ans: 3.502 kJ.
2. For the reaction : 2A (g) + 3B (g) 4C (g) + D (l) ; ∆H = –20 KJ/mole
Find the heat exchanged when 0.4 mole of A reacts with excess of B in a closed rigid container. The temperature is constant at 300 K. [R = 8.3 J/K mole]
Ans: B
Getting 3.5
A nitrogen-hydrogen mixture initially in the molar ratio of 1 : 3 reached equilibrium to form ammonia when 25% of the N2 and H2 had reacted. If the total pressure of the system was 21 atm, the partial pressure of ammonia at the equilibrium was:
(a) 4.5 atm
(b) 3.0 atm
(c) 2.0 atm
(d) 1.5 atm
Ans: A.
How?
(A) Enantiomer
(B) Diastereomers
(C) Meso
(D) Achiral
Ans: C.
Explain thru a mechanism.
20.
(A) CH3 – CH2 – CH3 & SN2
(B) CH3 – CH = CH2 & SN1
(C) CH3 – CH = CH2 & E2
(D) None
Ans: C.
Explant pls asap
Q5. For a reaction, 2X(s) + 2Y(s) → 2C(l) + D(g)
The qp at 27°C is –28 kcal mol–1, the qv is ________ Kcal mol–1
(A) –27.4
(B) +27.4
(C) –28.6
(D) 28.6
Help asap!
The volume of one mole ideal monatomic gas at temperature T on an adiabatic flask is increased from 1 to 2 litre at an external pressure of 1atm. Determine the final temperature......
Ans: bcd.
Exain B and D.
Ans: b
How?
Ans: B.
How?