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K D
Subject: Maths
, asked 1 week, 3 days ago
Solve this question. You don't have to use the concept of elementary transformation of a matrix. When I posted this question previously, the so called expert used this concept despite my instruction.
Answer
1
K D
Subject: Maths
, asked 1 week, 3 days ago
Solve this question. (Don't use the concept of elementary transformation of a matrix)
Answer
1
K D
Subject: Maths
, asked 1 week, 3 days ago
Answer this why
Answer
2
Dhaarna Bansal
Subject: Maths
, asked 1 week, 3 days ago
Ans this ques plz
Answer
1
Devika Krishnan
Subject: Maths
, asked 1 week, 3 days ago
Find the particular solution of the differential equation
y2+ x 2 dy/dx = x y dy/dx satisfying the given condition y=1 when x=1
Answer
1
Devika Krishnan
Subject: Maths
, asked 1 week, 3 days ago
Evaluate ∫ 3 x ‐ 1 dx
-------------
(x-1) (x-2 )(x-3)
Answer
1
Khushi Gupta
Subject: Maths
, asked 1 week, 4 days ago
Solve this question
Answer
1
Dhaarna Bansal
Subject: Maths
, asked 1 week, 4 days ago
Ans Q28 plz
Answer
1
Khushi Gupta
Subject: Maths
, asked 1 week, 4 days ago
All trigonometric identities of class 11 and 12
Answer
2
Khushi Gupta
Subject: Maths
, asked 1 week, 4 days ago
Evaluate ??this fast
Answer
1
Garima Dhanania
Subject: Maths
, asked 1 week, 5 days ago
Question
No
7
Answer
1
Panna Luhana
Subject: Maths
, asked 1 week, 6 days ago
In a large city the price of cherries is Rs 188 per kg and the supply is 16000 kg and he demand is 10,600 kg . When the price decreased to 146 Rs per kg and the supply also drops to 10,000 kg and demand rises to 12,700 kg. Assuming that the price-supply and price -demand are linear equation. Then :(i) Find price - supply equation
Answer
1
Dhaarna Bansal
Subject: Maths
, asked 1 week, 6 days ago
Ans q3 plz
Answer
1
Dhaarna Bansal
Subject: Maths
, asked 1 week, 6 days ago
Ans q1 plz
Answer
1
Surabhi
Subject: Maths
, asked 1 week, 6 days ago
Solve the following:-
Answer
1
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What are you looking for?

y2+ x 2 dy/dx = x y dy/dx satisfying the given condition y=1 when x=1

-------------

(x-1) (x-2 )(x-3)

No

7