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Khushboo
Subject: Maths
, asked on 10/3/18
"DO NOT SEND ANY LINKS".
Q. In the given figure AB = AC; angle A = 50 degree and angle ACD = 15 degree. Show that BC = CD.
Answer
2
Khushboo
Subject: Maths
, asked on 10/3/18
"DO NOT SEND ANY LINKS".
Answer the 1st question.
Q.1. In the given figure, PA
$\perp $
AB; PA = QB. If PQ intersects AB at M, show that M is the mid-point of both AB and PQ.
Answer
1
Khushboo
Subject: Maths
, asked on 8/9/17
Q. Using ruler and compasses only. Construct a rhombus ABCD with sides of length 4 cm, and diagonal AC of length 5 cm, measure
$<$
ABC.
Answer
2
Khushboo
Subject: Maths
, asked on 8/9/17
Q. Using ruler and compasses only, construct the quadrilateral ABCD in which < BAD = 45
^{∘}
. AD = AB = 6 CM, BC = 3.6 CM, CD = 5 CM. Measure < BCD.
Answer
1
Khushboo
Subject: Maths
, asked on 6/9/17
Answer the 39th question."PLEASE DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER".
Q.39. Find the measure of each lettered angle.
Answer
1
Khushboo
Subject: Maths
, asked on 6/9/17
Answer the 39th question."PLEASE DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER".
Q.39. Find the measure of each lettered angle.
Answer
1
Khushboo
Subject: Maths
, asked on 6/9/17
Q.38. In the adjoining figure, TR = TS,
$\angle 1=2\angle 2and\angle 4=2\angle 3$
. Prove that RB = SA.
Answer
1
Khushboo
Subject: Maths
, asked on 6/9/17
Answer the 37the question."DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER".
Q.37. In the adjoining figure, AB || DC. CE and DE bisects
$\angle BCDand\angle ADC$
respectively. Prove that AB = AD + BC.
Answer
2
Khushboo
Subject: Maths
, asked on 6/9/17
Answer to the 36th question."DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER".
Q.36. In the adjoining figure, AB = AC, D is a point in the interior of
$\u25b3$
ABC such that
$\angle $
DBC =
$\angle $
DCB. Prove that AD bisects
$\angle $
BAC of
$\u25b3$
ABC.
Answer
1
Khushboo
Subject: Maths
, asked on 20/8/17
Amswer the 22nd question."DON'T SEND THE SIMILAR QUERY,KINDLY PERFORM THE CORRECT AND STEP BY STEP CALCULATION".
Answer
1
Khushboo
Subject: Maths
, asked on 17/8/17
Answer the 22nd question.DON'T SEND THE SIMILAR QUERY,KINDLY PERFORM THE CORRECT AND STEP BY STEP CALCULATION".
Answer
2
Zeba Hasin Chowdhury
Subject: Maths
, asked 3 weeks, 5 days ago
Please help me with the following question :)
Answer
1
Zeba Hasin Chowdhury
Subject: Maths
, asked 3 weeks, 5 days ago
Please help me with this question-
Answer
2
Zeba Hasin Chowdhury
Subject: Maths
, asked 3 weeks, 5 days ago
Please help me out with this question :)
Answer
2
Zeba Hasin Chowdhury
Subject: Maths
, asked 4 weeks ago
In the figure,PQRS is a square.Arc AB is drawn with centre P and any radius less than PR, cutting SR at A and RQ at B. Prove that AS=BQ
Answer
1
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What are you looking for?

Q. In the given figure AB = AC; angle A = 50 degree and angle ACD = 15 degree. Show that BC = CD.

Answer the 1st question.

Q.1. In the given figure, PA$\perp $AB; PA = QB. If PQ intersects AB at M, show that M is the mid-point of both AB and PQ.

^{∘}. AD = AB = 6 CM, BC = 3.6 CM, CD = 5 CM. Measure < BCD.Q.39. Find the measure of each lettered angle.

Q.39. Find the measure of each lettered angle.

Q.37. In the adjoining figure, AB || DC. CE and DE bisects $\angle BCDand\angle ADC$ respectively. Prove that AB = AD + BC.

Q.36. In the adjoining figure, AB = AC, D is a point in the interior of $\u25b3$ ABC such that $\angle $ DBC = $\angle $ DCB. Prove that AD bisects $\angle $ BAC of $\u25b3$ ABC.