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Amitesh Kumar
Subject: Maths
, asked on 27/4/18
Plz fast:
4
.
If
one
root
of
the
equation
7
6
x
2
-
13
2
x
2
-
13
2
x
2
-
13
3
7
=
0
is
x
=
2
the
sum
of
all
other
five
roots
is
.
(
a
)
2
15
b
-
2
c
20
+
15
-
2
d
None
of
these
Answer
1
Jaanvi Agarwal
Subject: Maths
, asked on 26/4/18
Find no of solutions
x^2+y^2+z^2=1
2x^2+y^2+z^2=2
3x^2+2y^2+z^2=4
Answer
1
Varad Sawant
Subject: Maths
, asked on 26/4/18
Without expanding evaluate the determinant
Q.
∆
=
sin
α
cos
α
sin
(
α
+
δ
)
sin
β
cos
β
sin
(
β
+
δ
sin
γ
cos
γ
sin
(
γ
+
δ
)
Answer
1
Apurva Inamdar
Subject: Maths
, asked on 25/4/18
14th question
Answer
1
Ruba Balu
Subject: Maths
, asked on 23/4/18
29th one
Q.29. If
A
=
2
-
3
3
4
, find the value of k such that
A
2
=
k
A
-
2
I
. Hence find
A
-
1
.
Answer
1
Ruba Balu
Subject: Maths
, asked on 23/4/18
24th
Answer
1
Ruba Balu
Subject: Maths
, asked on 23/4/18
17th ans pls.. No links
Q.17. Using properties of determinants show that
1
a
a
2
-
b
c
1
b
b
2
-
a
c
1
c
c
2
-
a
b
=
0
Answer
4
Aaryaman Bhardwaj
Subject: Maths
, asked on 22/4/18
Q. If determinant is positive , while a , b, c are the roots of the equation p x
3
+ 2 x
2
-3 x + r = 0 , p is not zero then find range of 'r'
Answer
1
Vivek Kumar
Subject: Maths
, asked on 18/4/18
Plzz answer to this questions
Q
If
the
value
of
the
determinant
a
1
1
1
b
1
1
1
c
is
positive
,
then
which
of
the
inequality
is
true
?
a
abc
>
1
b
abc
>
-
8
c
abc
<
-
8
d
abc
<
1
Answer
1
Archana
Subject: Maths
, asked on 15/4/18
21
17
7
10
24
22
6
10
6
8
2
3
6
7
1
2
=
(a) 2 (b) –1 (c) 3 (d) none of these
Answer
1
Archana
Subject: Maths
, asked on 15/4/18
explain this sum...:
3
.
I
f
A
+
B
+
C
=
π
,
then
sin
2
A
cot
A
1
sin
2
B
cot
B
1
sin
2
C
cot
1
=
(a) 1 (b) -1
(c) 2 (d) None of these
Answer
1
Ranjan Shivam
Subject: Maths
, asked on 12/4/18
determinant of 4*4 find f(X)
Q. Find f (x)
x
a
a
a
a
x
a
a
a
a
x
a
a
a
a
x
=
x
+
3
a
f
x
Answer
1
Avinash R
Subject: Maths
, asked on 6/4/18
Solve Det a p x + Det a p x = ?
b q y b q y
c r z c r z
Answer
1
Yagyam Aggarwal
Subject: Maths
, asked on 4/4/18
Pls solve 2nd part
Q. (ii)
a
b
c
a
2
b
2
c
2
b
+
c
c
+
a
a
+
b
=
a
-
b
b
-
c
c
-
a
a
+
b
+
c
Answer
1
Yagyam Aggarwal
Subject: Maths
, asked on 4/4/18
Pls solve 1st part of 2nd question
Q.2. Prove the following :
(i)
1
1
1
a
b
c
b
c
c
a
a
b
=
a
-
b
b
-
c
c
-
a
Answer
1
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What are you looking for?
x^2+y^2+z^2=1
2x^2+y^2+z^2=2
3x^2+2y^2+z^2=4
Q.
Q.29. If , find the value of k such that . Hence find .
Q.17. Using properties of determinants show that
(a) 2 (b) –1 (c) 3 (d) none of these
(a) 1 (b) -1
(c) 2 (d) None of these
Q. Find f (x)
b q y b q y
c r z c r z
Q. (ii)
Q.2. Prove the following :
(i)