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Riya Verma

Subject: Maths, asked on 1/3/18

Plz check whether it is correct or not because the answer is -xdy/dx square whereas i m getting in plus

Shanaya

Subject: Maths, asked on 26/2/18

Q.20

$20 . Solve : \sqrt{1 + x^{2} + y^{2} + x^{2} y^{2}} dx + xydy = 0 [\sqrt{1 + y^{2}} = - \sqrt{1 + x^{2} - \log |\frac{\sqrt{1 + x^{2}}}{x} - \frac{1}{x}|} + C]$

Shanaya

Subject: Maths, asked on 26/2/18

12) Show that the differential equation $2 y e^{x / y} d x + (y - 2 x e^{\frac{x}{y}}) d y = 0$ is homogenous and find the particular solution if y (0) = 1.

Vinuthna Terala

Subject: Maths, asked on 25/2/18

Q10 asap
Q.10. Form the differential equation of the family of circles touching the x-axis at origin.

Shanaya

Subject: Maths, asked on 23/2/18

How did we integrated RHS and git the answer in log?

$y (x^{2} - 1) = \int \frac{1}{x^{2} - 1} d x + C y (x^{2} - 1) = \frac{1}{2} \log |\frac{x - 1}{x + 1}| + C .$

Shvaetha Kumaravel

Subject: Maths, asked on 20/2/18

Solve the differential equation : (2x+3+2y)dy/dx = (x+1+y)

Shvaetha Kumaravel

Subject: Maths, asked on 20/2/18

y=sin^-1(root 1-x + root 1+x / 2) find dy/dx

Brendan

Subject: Maths, asked on 20/2/18

Q. Find the order and degree of the differential equation $\frac{d^{2} y}{d x^{2}} + \sin (\frac{d y}{d x}) = 0$

Brendan

Subject: Maths, asked on 20/2/18

Q. Write the order and degree of the differential equation $y = x \frac{d y}{d x} + a \sqrt{1 + {(\frac{d y}{d x})}^{2}}$

Brendan

Subject: Maths, asked on 20/2/18

Q. Solve the differential equation $\frac{d y}{d x} = s e c y$ , given y (0) = 1.

Brendan

Subject: Maths, asked on 19/2/18

Q. Solve the differential equation $\frac{d y}{d x} + \sqrt{\frac{1 - y^{2}}{1 - x^{2}}} = 0$ .

Brendan

Subject: Maths, asked on 19/2/18

Q. Find the order and degree of the differential equation ${[5 + {(\frac{d y}{d x})}^{2}]}^{\frac{5}{3}} = x^{5} (\frac{d^{2} y}{d x^{2}})$

Brendan

Subject: Maths, asked on 19/2/18

Q. Write the order and degree of the differential equation $2 \frac{d^{2} y}{d x^{2}} + 3 \sqrt{1 - {(\frac{d y}{d x})}^{2} - y} = 0$ .

Brendan

Subject: Maths, asked on 19/2/18

Q. Find the order and degree of the differential equation $y = \frac{d y}{d x} + \sqrt{1 + {(\frac{d y}{d x})}^{2}}$

Aditi Sharma

Subject: Maths, asked on 17/2/18

Is this correct ?

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