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Divyansh Saxena
Subject: Chemistry
, asked on 4/2/18
how many milliliters of 0.0100 koh are needed to completely neutralize the Hcl in 300ml of a hrdrochloric acid solution that has ph 2.25??
Answer
1
Chharishma.r.nayaka
Subject: Chemistry
, asked on 3/2/18
Plz ans...I need it urgently...plz
Q.34.A). Assuming complete dissociation, calculate the pH value of 0.005 M NaOH.
Answer
3
Archit Anand K.p.
Subject: Chemistry
, asked on 2/2/18
CO2(g)+C(s)->2 CO(g)
What will happen if C(s) is removed will it have any effect on thr direction of reaction as it is solid and the concenteation solids are considered constant.Explain
Answer
1
Anika Kapoor
Subject: Chemistry
, asked on 2/2/18
Pls ans.
Q.56. How many grams of NaOH must be dissolved in 100 ml of water to give a solution with pH = 11.7 at room temperature ?
Answer
1
Anika Kapoor
Subject: Chemistry
, asked on 2/2/18
Please answer
Q
.
51
.
C
a
l
c
u
l
a
t
e
H
3
O
+
a
n
d
O
H
-
i
n
c
a
s
e
o
f
s
o
f
t
d
r
i
n
k
h
a
v
i
n
g
p
H
=
4
.
4
.
Answer
2
Abhishek Gupta
Subject: Chemistry
, asked on 1/2/18
Q. Solid
N
H
4
I
dissociates according to the reaction at 400 K
N
H
4
I
(
s
)
⇌
N
H
3
(
g
)
+
H
I
(
g
)
;
K
p
=
16
a
t
m
. In presence of catalyst, HI dissociates into
H
2
a
n
d
I
2
a
s
2
H
I
⇌
H
2
+
I
2
If partial pressure of
H
2
at this temp is 1 atm in the container when both the equilibrium exist simultaneously, calculate
K
p
value of second equilibrium (for the dissociation of HI)
0.104
1.04
10.4
104
Answer
1
Shivam Desale
Subject: Chemistry
, asked on 31/1/18
Q. Which has the highest degree of ionization?
a. 1 M N
H
3
b. 0.001 M N
H
3
c. 0.1 M N
H
3
d. 0.0001 M N
H
3
Answer
1
Shivam Gupta
Subject: Chemistry
, asked on 29/1/18
what is the role of camopy
Answer
1
Tulsi Mehta
Subject: Chemistry
, asked on 26/1/18
Plz explain this paragraph
The solubility of salts of weak acids like phosphates increases at lower pH. This is because at lower pH the concentration of the anion decreases due to its protonation. This in turn increase the solubility of the salt so that K
sp
= Q
sp
. We have to satisfy two equilibria simultaneously i.e.,
K
sp
= [M
+
] [ X
–
]
HX (aq)
⇌
H
+
(aq) + X
–
(aq) ;
Answer
1
Tulsi Mehta
Subject: Chemistry
, asked on 26/1/18
For taking negative antilog of 4.75( for example) , we subtract 0.75 from 1.
Then we find value from antilog table.The value is 1778.
So antilog is 1.778 x 10^-5.
PLZ TELL ME HOW DO WE PUT HE NEGATIVE SIGN AFTER 1 ?
Answer
1
Tulsi Mehta
Subject: Chemistry
, asked on 26/1/18
In the circled step, why isnt concentration of 0.08-0.08x?
And in this question why arent we
using c alpha method ?
Answer
1
Tulsi Mehta
Subject: Chemistry
, asked on 26/1/18
In example 7.19 from ncert, the following expression is given. Plz tell how to get this.
Answer
1
Shivam Desale
Subject: Chemistry
, asked on 25/1/18
Plz solve:
Q.53. 100 ml of 0.2 M HCl are mixed with 100 ml of 0.2 M
C
H
3
C
O
O
H
, the pH of the resulting solution would be nearly.
(A) 1
(B) 0.7
(C) 1.3
(D) 1.6
Answer
1
Tulsi Mehta
Subject: Chemistry
, asked on 25/1/18
When a product is removed from a reaction to boost reaction in forward direction should be there simultaneous addition of reactants also ? Because if reaction has to take place then reactants have yo be present .
Answer
1
Tulsi Mehta
Subject: Chemistry
, asked on 25/1/18
Plz expand these
1)Kc = e ^ -5.569
2)ln(2*10^14)
Answer
1
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What are you looking for?
Q.34.A). Assuming complete dissociation, calculate the pH value of 0.005 M NaOH.
What will happen if C(s) is removed will it have any effect on thr direction of reaction as it is solid and the concenteation solids are considered constant.Explain
Q.56. How many grams of NaOH must be dissolved in 100 ml of water to give a solution with pH = 11.7 at room temperature ?
Q. Solid dissociates according to the reaction at 400 K
. In presence of catalyst, HI dissociates into
If partial pressure of at this temp is 1 atm in the container when both the equilibrium exist simultaneously, calculate value of second equilibrium (for the dissociation of HI)
Q. Which has the highest degree of ionization?
a. 1 M N
b. 0.001 M N
c. 0.1 M N
d. 0.0001 M N
The solubility of salts of weak acids like phosphates increases at lower pH. This is because at lower pH the concentration of the anion decreases due to its protonation. This in turn increase the solubility of the salt so that Ksp = Qsp. We have to satisfy two equilibria simultaneously i.e.,
Ksp = [M+] [ X –]
HX (aq) H+ (aq) + X– (aq) ;
Then we find value from antilog table.The value is 1778.
So antilog is 1.778 x 10^-5.
PLZ TELL ME HOW DO WE PUT HE NEGATIVE SIGN AFTER 1 ?
And in this question why arent we
using c alpha method ?
Q.53. 100 ml of 0.2 M HCl are mixed with 100 ml of 0.2 M , the pH of the resulting solution would be nearly.
(A) 1
(B) 0.7
(C) 1.3
(D) 1.6
1)Kc = e ^ -5.569
2)ln(2*10^14)