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R. Lasyapriya
Subject: Math
, asked on 4/5/18
Find the value of t ratios (trigonometric ratios)please solve (vi) bit .
Please I need your help experts.:
$\left(\mathrm{vi}\right)\mathrm{tan\theta}=\frac{2\mathrm{mn}}{{\mathrm{m}}^{2}-{\mathrm{n}}^{2}}$
Answer
2
R. Lasyapriya
Subject: Math
, asked on 4/5/18
Solve this Query .
Please answer it as soon as possible.
Answer it as soon as possible .
$73.Ifcot\theta =\frac{1}{\sqrt{3}},showthat\frac{{\mathrm{sin}}^{2}\theta}{1+{\mathrm{cos}}^{2}\theta}=\frac{3}{5}$
Answer
2
R. Lasyapriya
Subject: Math
, asked on 4/5/18
Solve Question 72 .
I have solved the sum but I am doubtful.
Experts please solve .
Solve thos query as soon as possible.
Q.72. If
$\mathrm{tan}\theta =\frac{5}{4}$
, find the value of
$\frac{3\mathrm{sin}\theta +4\mathrm{cos}\theta}{3\mathrm{sin}\theta -4\mathrm{cos}\theta}$
.
Answer
4
R. Lasyapriya
Subject: Math
, asked on 1/5/18
Q.):- In the given figure, ABCD is a rectangle with DC = 8 cm & BC = 6cm. Line segment CM is drawn making an angle of
$30\xb0$
with DC intersecting Ad in M. Find the length of CM & DM.
Answer
3
R. Lasyapriya
Subject: Math
, asked on 1/5/18
Solve this please. Answer this as soon as possible . I WANT This Question solution fast.
Answer
1
Vaishnavi G
Subject: Math
, asked on 30/4/18
A triangle can be made only when we have three non collinear points, but in trigonometry when we are finding sin cos or tan of angle 0 or 90 degree, we do not get three non collinear points, then how can we conclude that it is a triangle or find anything about it by assuming it a triangle! Answer fast
Answer
1
R. Lasyapriya
Subject: Math
, asked on 29/4/18
Solve .
Q. Find the value of
$\theta \left(0\xb0\theta 90\xb0\right)if2{\mathrm{cos}}^{2}\theta =\frac{1}{2}$
Answer
4
R. Lasyapriya
Subject: Math
, asked on 29/4/18
$Withoutu\mathrm{sin}gtrigonometrictables,findthevalueofthefollowing:\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}cot\theta \mathrm{tan}(90\xb0-\theta )-sec(90\xb0-\theta )\mathrm{cos}ec\theta +\sqrt{3}\mathrm{tan}12\xb0\mathrm{tan}60\xb0\mathrm{tan}78\xb0\phantom{\rule{0ex}{0ex}}$
Please dont send any links.
Solve this Query.
Answer
1
R. Lasyapriya
Subject: Math
, asked on 29/4/18
Solve this :
Please don't send any links please .
$25.\phantom{\rule{0ex}{0ex}}\left(\mathrm{a}\right)\mathrm{Without}\mathrm{using}\mathrm{trigonometrical}\mathrm{tables},\mathrm{evaluate}\phantom{\rule{0ex}{0ex}}\frac{7}{2}.\frac{\mathrm{cos}70\xb0}{\mathrm{sin}20\xb0}+\frac{3}{2}\times \frac{\mathrm{cos}55\xb0\mathrm{cosec}35\xb0}{\mathrm{tan}5\xb0\mathrm{tan}25\xb0\mathrm{tan}45\xb0\mathrm{tan}85\xb0\mathrm{tan}65\xb0}$
Answer
1
Bhavya Sri Jonnala
Subject: Math
, asked on 29/4/18
sec17/cosec73 + tan68/cot22 + cos
^{2 }
44 + cos
^{2 }
46
Answer
1
Bhavya Sri Jonnala
Subject: Math
, asked on 29/4/18
4/3 tan
^{2 }
30 + sin
^{2 }
60 - 3cos
^{2 }
60 + 3/4tan
^{2 }
60 - 2tan
^{2 }
45
Answer
1
R. Lasyapriya
Subject: Math
, asked on 26/4/18
Question 15 and Question 16 i] questikn please help me and answer it as soon.as possib?e.
Answer
2
R. Lasyapriya
Subject: Math
, asked on 25/4/18
Q.13. Find the value of
$\frac{{\mathrm{cos}}^{2}20\xb0{\mathrm{cos}}^{2}70\xb0}{{\mathrm{sin}}^{2}31\xb0{\mathrm{sin}}^{2}59\xb0}+{\mathrm{sin}}^{2}64\xb0+\mathrm{cos}64\xb0.\mathrm{sin}26\xb0$
Answer
1
R. Lasyapriya
Subject: Math
, asked on 24/4/18
Solve the Question 5
Q.5. In the figure, ABC is a right angled triangle, D is the mid-point of BC. Show that
$\frac{\mathrm{tan}\theta}{\mathrm{tan}\varphi}=\frac{1}{2}$
.
Answer
1
R. Lasyapriya
Subject: Math
, asked on 24/4/18
Please solve this Question and dont send any links to this question.
Experts I need your help .
Thankyou very much for helping me .
Answer it as soon as possible.
Answer
4
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Please I need your help experts.:

$\left(\mathrm{vi}\right)\mathrm{tan\theta}=\frac{2\mathrm{mn}}{{\mathrm{m}}^{2}-{\mathrm{n}}^{2}}$

Please answer it as soon as possible.

Answer it as soon as possible .

$73.Ifcot\theta =\frac{1}{\sqrt{3}},showthat\frac{{\mathrm{sin}}^{2}\theta}{1+{\mathrm{cos}}^{2}\theta}=\frac{3}{5}$

I have solved the sum but I am doubtful.

Experts please solve .

Solve thos query as soon as possible.

Q.72. If $\mathrm{tan}\theta =\frac{5}{4}$, find the value of $\frac{3\mathrm{sin}\theta +4\mathrm{cos}\theta}{3\mathrm{sin}\theta -4\mathrm{cos}\theta}$.

Q. Find the value of $\theta \left(0\xb0\theta 90\xb0\right)if2{\mathrm{cos}}^{2}\theta =\frac{1}{2}$

Please dont send any links.

Solve this Query.

Please don't send any links please .Solve this :$25.\phantom{\rule{0ex}{0ex}}\left(\mathrm{a}\right)\mathrm{Without}\mathrm{using}\mathrm{trigonometrical}\mathrm{tables},\mathrm{evaluate}\phantom{\rule{0ex}{0ex}}\frac{7}{2}.\frac{\mathrm{cos}70\xb0}{\mathrm{sin}20\xb0}+\frac{3}{2}\times \frac{\mathrm{cos}55\xb0\mathrm{cosec}35\xb0}{\mathrm{tan}5\xb0\mathrm{tan}25\xb0\mathrm{tan}45\xb0\mathrm{tan}85\xb0\mathrm{tan}65\xb0}$

^{2 }44 + cos^{2 }46^{2 }30 + sin^{2 }60 - 3cos^{2 }60 + 3/4tan^{2 }60 - 2tan^{2 }45$\frac{{\mathrm{cos}}^{2}20\xb0{\mathrm{cos}}^{2}70\xb0}{{\mathrm{sin}}^{2}31\xb0{\mathrm{sin}}^{2}59\xb0}+{\mathrm{sin}}^{2}64\xb0+\mathrm{cos}64\xb0.\mathrm{sin}26\xb0$

Q.5. In the figure, ABC is a right angled triangle, D is the mid-point of BC. Show that $\frac{\mathrm{tan}\theta}{\mathrm{tan}\varphi}=\frac{1}{2}$.

Experts I need your help .

Thankyou very much for helping me .

Answer it as soon as possible.